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Questions - neighbours

Create dummy variable for all neighborhood region depending on another dummy variable (sf object)

I have a spatial dataframe (sf) of all European NUTS2 regions. Within this sf object certain regions have a dummy = 1, and others a dummy = 0. How can I create a new dummy (lets say "dummy_neighb...
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Tom

spatial

sf

dummy-variable

neighbours

Votes: 0

Answers: 1

Latest Answer

For the time being I have this work-around. But I guess there musst be an easier solution? # load packages library(sf) library(here) library(tidyverse) library(spdep) library(expp) # import nuts 2 sf...
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Tom

Spawning pathfinder neighbours

I am trying to spawn the neighbours of my path finder but when doing so the original path (path) blue also becomes covered up. I have tried switching of the order of spawn but this does not seem to he...
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Krellex

c#

unity-game-engine

path-finding

neighbours

Votes: 0

Answers: 1

Latest Answer

A typical simple solution is to check if the node is part of the path before adding. A HashSet can be good for this, but you will need something that can be reliably compared. Perhaps something like t...
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JonasH

Most efficient way to check cells and change neighbors matching a condition in a dataframe

I'm using a pandas dataframe to store a dynamic 2D game map for a rougelike style game map editor. The player can draw and erase rooms. I need to draw walls around these changing rooms. I have this: 0...
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JackBox

python

pandas

dataframe

numpy

neighbours

Votes: 0

Answers: 1

Latest Answer

What you want to do is called a binary dilation. You can do this on the underlying numpy array with scipy.ndimage.morphology.binary_dilation: from scipy.ndimage.morphology import binary_dilation impor...
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mozway

numpy store the neigborhood as new (3rd) dimension into matrix

Given a numpy array like: L = 2 np.random.randint([-1,1],size=(L,L), dtype=int) array([[1, -1], [-1, 1]]) How can I transform it into an array of similar shape (efficiently) np.random.choice([...
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Georg Heiler

python

numpy

matrix

convolution

neighbours

Votes: 0

Answers: 1

Latest Answer

You can try the following: #sample array a = np.arange(9).reshape(3, 3) print(a) It gives: [[0 1 2] [3 4 5] [6 7 8]] Compute the array of neighbors: p = np.pad(a, 1) out = np.empty((*a.shape, 4), ...
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bb1

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