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Questions - rounding

How to round integer number using precision in flutter

I am trying to make the Y axis intervals of linechart dynamic in flutter. Here the MaxVal will get the maximum value of the Y axis. int interval = (maxVal/6).toInt(); int length = interval.toString()....
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Midlaj

flutter

dart

rounding

Votes: 0

Answers: 1

Latest Answer

I'm assuming that you're asking to round a (non-negative) integer to its most significant base-10 digit. A general way to round non-negative integers is to add half of the unit you want to round to a...
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jamesdlin

Force R to always round up to two decimal places

I am looking for a solution but could not find a solution yet. Really basic, i want R to always round up my numbers until two decimal places so 2,3421 should be rounded to 2,35 a <- 2.3423 format(r...
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Max H.

r

rounding

Votes: 0

Answers: 1

Latest Answer

If your numbers are in a numeric vector : format(round(a,digits=2),nsmall=2) which gives a character vector. The format function is there so that 1 is displayed as 1.00 and not 1 for example. If you ...
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Valkyr

signif doesn&#39;t give me the correct number of significant digits in R

I want to round my data with significant digits. Therefore I am using signif to achieve that. For example: signif(0.0054324, digits=2) [1] 0.0054 However, I realised that there are some cases where s...
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emr2

r

rounding

significant-digits

Votes: 0

Answers: 2

Latest Answer

This little function should give you the results you are looking for. It works by only applying signif to the fractional part of your number, while preserving the integer part. mysignif <- function...
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Allan Cameron

Strange behavior of round() when 5 is the digit to round

When 5 is the last digit, the round() function doesn't always round up. Instead, it alternates between rounding up and rounding down. Example: print(round(1.5)) >>>2 print(round(2.5)) >>...
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Jock

python

rounding

Votes: 0

Answers: 2

Latest Answer

There's a possible work-around for the round function's behaviour. import math some_value = 35 print(math.ceil(someValue / 10) * 10 if some_value % 5 == 0 else round(some_value, -1)) This code che...
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HerrAlv&#233;

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