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Questions - python-3.10

How to skip certain part strings if the coefficient is zero?

In this question, we want to return the function like this result but I do not want things like 0^5 to occur(because 0^5 is equal to 0 and I do not want to show that, how can I write a code to let the...
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beginner.py

python

python-3.x

class

python-3.10

Votes: 0

Answers: 1

Latest Answer

Here is the code I think you want, the order of the coefficients is wrong but That wasn't the main issue. class Poly(): def __init__(self, coe=None): if coe is None: coe = [] ...
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Eilonlif

I am trying to install PyQt6 and am getting metadata error

New to Python. Attempting to install PyQt6. This is my error. Any suggestions? Preparing metadata (pyproject.toml) ... error error: subprocess-exited-with-error × Preparing metadata (pyproject.tom...
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Ed Thompson

python

python-3.10

pyqt6

Votes: 0

Answers: 1

Latest Answer

What version of python did you install? Because i had the same problem and for me the update to a recent version of python (3.9 to 3.10) have solved the problem
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Elisa Simoni

Is there a way to use a regex inside a python pattern match?

This is common across functional languages that support pattern matching, so my intuition wants this to be possible. I am looking for something like: match string: case "[a-zA-Z]": ...
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777bpc

python

regex

pattern-matching

python-3.10

Votes: 0

Answers: 2

Latest Answer

Python's re module does regex, so you can use if-elif-else: import re string = "test_string" if re.match("[a-zA-Z]", string): # string starts with a letter elif re.match("...
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Ukulele

Remove dictionary from list if it contains forbidden value

I have a list of dictionaries: my_dicts = [ {'name': 'aaa', 'codename': 'bbbb', 'type': 'cccc', 'website': 'url1'}, {'name': 'aaa2', 'codename': 'bbbb2', 'type': 'cccc2', 'product_url'...
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Howins

python

list

dictionary

python-3.10

Votes: 0

Answers: 2

Latest Answer

You can use a list comprehension with all(), retaining only the dictionaries that do not have a key-value pair where the value appears in my_list: [item for item in my_dict if all(url not in item.valu...
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BrokenBenchmark

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