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Questions - janitor

Function for clean factor levels (Adoption from janitor::clean_names())

I was stupid and coded a lot of my factor labels with "(" or "/". In general it worked for me but now I am at a point (glht(mod, linfct = c("……"))) where this doesn't wor...
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Eco007

r

data-cleaning

tidy

janitor

Votes: 0

Answers: 1

Latest Answer

clean_character can use remove argument library(clean) library(dplyr) library(sjlabelled) i_temp <- temp %>% mutate(across(where(is.factor), ~ as.factor(clean_character(.x, remove = ...
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akrun

preserve specific characters with janitor clean_names

I am using janitor clean_names()/make_clean_names() and would like to preserve certain characters. I think replace is the argument I should be using and that works for some cases. For example, I can r...
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burger

r

janitor

Votes: 0

Answers: 1

Latest Answer

One of the main reasons to use make_clean_names is to return a standard name that can be parsed without having to use backquotes. The package uses _ as default replacement when there is a non-standard...
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akrun

Making 2-way graph (ggplot2) out of a tabyl table changing values

male FALSE TRUE 0 50.0% 66.7% 1 50.0% 33.3% structure(list(male = 0:1, `FALSE` = c("50.0%", "50.0%"), `TRUE` = c("66.7%", "33.3%")), row.names = c(NA...
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R novice

r

ggplot2

graph

replace

janitor

Votes: 0

Answers: 1

Latest Answer

You can try a tidyverse. The trick is to transform the data from wide to long since this is the prefered input for ggplot. Here I used pivot_longer, but you can also use reshape or melt. library(tidyv...
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Roman

Using base::function with tidyverse and janitor to create several crosstables in R

I have a Data Frame with Survey Data and want to create crosstables between every dimension and diagnosis. I succesfully did this with dplyr and janitor: library(tidyverse) library(janitor) survey &l...
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Ntgllr

r

tidyverse

janitor

Votes: 0

Answers: 1

Latest Answer

You were very close. Try using .data[[ to reference the variables. There were also a few typos: Missing closing ) Missing %>% operator Wrong variable name. xtable_fun <- function(data, dimensi...
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user10917479

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