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Questions - deviation

Mean and Standard deviation of interpolated datasets (R)

I have 8 data sets that I have interpolated so the x axis spacing is the same but they are different lengths ranging from 800-1200 points. What I would like to do is then calculate the mean of each y ...
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James Blackwell

r

dataset

mean

standards

deviation

Votes: 0

Answers: 1

Latest Answer

Instead of doing this separately and creating multiple objects, we may loop over the list 'S' with lapply do.call(rbind, lapply(S, function(x) { x1 <- approx(x[["K"]], x[["Sh...
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akrun

How to implement a loop over all columns within a calculation in pandas?

I'm new to pandas and python and I'm struggling with the implementation of loops in my code. I hope that someone can help me. I have the following Dataframe: import pandas as pd from pandas import Tim...
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Kats

python

pandas

loops

iteration

deviation

Votes: 0

Answers: 3

Latest Answer

you could use str.contains to choose the variables containing 'forecast', and apply afterwards: df.loc[:,df.columns.str.contains('forecast')].apply(lambda x: (x-df['actual_value'])/df['actual_value'])...
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DHJ

Finding the average and standard deviation of a data set

I have a laser that is sent through a signal splitter. 90% of the light goes into a diffuser and that is detected by a Photomultiplier tube (PMT). The other 10% of the signal goes to a separate silico...
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Rachel Fister

numpy

average

normalization

deviation

Votes: 0

Answers: 1

Latest Answer

It seems you want to calculate the mean and standard deviation over three lists. import numpy as np PMT1 = ([-60,-57,-54,-51,-48,-45,-42,-39], [7.099,7.317,7.543,7.811,7.955,8.194,8.292,8.558]) diode...
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Mr. T

Is there a way to find a deviation between a1=[] and a2=[] in Python?

We have these arrays in python: a1 = [0, 1, 2, 3] a2 = [0, 1.1, 2.2, 3.1] and want to find the deviation between a1 and a2. And sorry, we do not know what's such a type of deviation is named, but pro...
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akakakakakkaa

python

arrays

statistics

standard-deviation

deviation

Votes: 0

Answers: 1

Latest Answer

You can find the sum of squared distances (as clarified in the comments) by using sum() and zip(): distance = sum([(elem1 - elem2)**2 for elem1, elem2 in zip(a1, a2)])
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BrokenBenchmark

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