1 year ago
#176600
robertspierre
Know which parts a day contains
The dateparser library set missing parts of a date to today's values.
Example:
>>> import dateparser
>>> dateparser.parse("2015")
datetime.datetime(2015, 2, 14, 0, 0)
How to know which parts a date really contains?
(and thus which parts were set to today's values by the library)?
This is what I've come up with.
Is there a more efficient way?
date_str = input('Type a date: ')
settings = {"REQUIRE_PARTS": ["year"]}
res = dateparser.parse(date_str, settings=settings)
if res is None:
print("Invalid Date")
return
settings = {"REQUIRE_PARTS": ["year", "month"]}
res = dateparser.parse(date_str, settings=settings)
if res is None:
print("Date has year only")
return
settings = {"REQUIRE_PARTS": ["year", "month", "day"]}
res = dateparser.parse(date_str, settings=settings)
if res is None:
print("Date has year and month")
return
print("Date has year, month and day")
python
date
datetime
date-parsing
dateparser
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